1) Derived truth table through function using SOP(Sum Of Product):- Simple Rules:- In SOP 0=(')like A' and 1 like A,In SOP we ...
1)Derived truth table through function using SOP(Sum Of Product):-
Simple Rules:- In SOP 0=(')like A' and 1 like A,In SOP we grasp 1 instead of o.
Q.1)Z(ABC)=Σ(3,5,6,7)
Sol.)Z(ABC)=A'BC+AB'C+ABC'+ABC
Q.2)Z(ABC)=Σ(0,1,5,7)
Sol.)Z(ABC)=A'B'C'+A'B'C+AB'C+ABC
2)Derived function through truth table using SOP:-
Q.1):
Sol.)Z(ABC)=A'B'C'+A'B'C+AB'C+ABC
Q.2):-
Sol.) Z(ABC)=A'BC+AB'C+ABC'+ABC
Simple Rules:- In SOP 0=(')like A' and 1 like A,In SOP we grasp 1 instead of o.
Q.1)Z(ABC)=Σ(3,5,6,7)
Sol.)Z(ABC)=A'BC+AB'C+ABC'+ABC
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 0 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 0 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 1 |
1 | 1 | 1 | 1 |
Q.2)Z(ABC)=Σ(0,1,5,7)
Sol.)Z(ABC)=A'B'C'+A'B'C+AB'C+ABC
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 1 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 0 |
1 | 0 | 0 | 0 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
2)Derived function through truth table using SOP:-
Q.1):
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 1 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 0 |
1 | 0 | 0 | 0 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
Sol.)Z(ABC)=A'B'C'+A'B'C+AB'C+ABC
Q.2):-
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 0 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 0 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 1 |
1 | 1 | 1 | 1 |
Sol.) Z(ABC)=A'BC+AB'C+ABC'+ABC
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