1) Derived truth table through function (Boolean Expression) using POS(Product of Sum):- Simple Rules:- In POS 1=(')like A' a...
1)Derived truth table through function(Boolean Expression) using POS(Product of Sum):-
Simple Rules:- In POS 1=(')like A' and 0 like A,In POS we grasp 0 instead of 1.
Q.1)Z(ABC)=(A+B+C').(A+B'+C).(A'+B+C')
Q.2)Z(ABC)=(A+B+C).(A+B'+C).(A'+B+C').(A'+B'+C).(A'+B'+C')
Sol.):-
2)Derived function through truth table using POS:-
Q.1):-
Sol.) (A+B+C').(A'+B+C).(A'+B'+C')
Q.2):-
Sol.) (A+B+C').(A+B'+C).(A'+B+C')
Simple Rules:- In POS 1=(')like A' and 0 like A,In POS we grasp 0 instead of 1.
Q.1)Z(ABC)=(A+B+C').(A+B'+C).(A'+B+C')
Sol.):-
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 0 |
Q.2)Z(ABC)=(A+B+C).(A+B'+C).(A'+B+C').(A'+B'+C).(A'+B'+C')
Sol.):-
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 0 |
0 | 0 | 1 | 1 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 0 |
2)Derived function through truth table using POS:-
Q.1):-
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 1 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 0 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 1 |
1 | 1 | 1 | 0 |
Sol.) (A+B+C').(A'+B+C).(A'+B'+C')
Q.2):-
A | B | C | Z |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 0 |
Sol.) (A+B+C').(A+B'+C).(A'+B+C')
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